Answer:
Hello,
k=-3 and h=-2
Step-by-step explanation:
[tex]5\ is\ a \ root \of \ x^2+(k-1)*x-5=0\\\\5^2+(k-1)*5-5=0\\\\5*(k-1)+20=0\\\\k-1=\dfrac{-20}{5} \\\\k=-4+1\\\\\boxed{k=-3}\\[/tex]
h+1 is thus a root of x²+(-3-1)*x-5=0
x²-4x-5=0
x²+x-5x-5=0
x(x+1)-5(x+1)=0
(x+1)(x-5)=0
h+1=-1
h=-2
