The answer is 1
Use the discramnt formula
[tex] {b {}^{2} - 4ac } [/tex]
Where a is 81, B is 18, and c is 1
We get
[tex]18 {}^{2} - 4(81)(1)[/tex]
We then get 324-324=0
Which equal 0. Since the discramnt produce 0, the number of solution is one and repeated.