Respuesta :

The word CALCULUS contains

2 C's + 1 A + 2 L's + 2 U's + 1 S = 8 letters, in all.

The number of distinct permutations of all these 8 letters

taken together is

... ( 8! ) / [ (2!) (1!) (2!) (2!) (1!) ]

= [ 8 · (7!) ] / 8

= 7 · (6!)

= 7 ( 720 )

= 5040 ........................................... .

Otras preguntas