Answer:
[tex]\large\boxed{d.\ (-4,\ 0)}[/tex]
Step-by-step explanation:
The formula of a midpoint of a segment AB with endpoints at A(x₁, y₁) and B(x₂, y₂):
[tex]M_{AB}\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)[/tex]
We have the points F(-5, -3) and G(-3, 3).
Substitute:
[tex]M_{FG}(x,\ y)\\\\x=\dfrac{-5+(-3)}{2}=\dfrac{-8}{2}=-4\\\\y=\dfrac{-3+3}{2}=\dfrac{0}{2}=0[/tex]
