Answer:
[tex]\huge\boxed{x=-3}[/tex]
Step-by-step explanation:
[tex]4x+2(x-3)=3x+x-12\qquad|\text{use the distributive property}\\\\4x+(2)(x)+(2)(-3)=3x+x-12\\\\4x+2x-6=3x+x-12\qquad|\text{combine like terms}\\\\(4x+2x)-6=(3x+x)-12\\\\6x-6=4x-12\qquad|\text{add 6 to both sides}\\\\6x-6+6=4x-12+6\\\\6x=4x-6\qquad|\text{subtract}\ 4x\ \text{from both sides}\\\\6x-4x=4x-4x-6\\\\2x=-6\qquad|\text{divide both sides by 2}\\\\\dfrac{2x}{2}=\dfrac{-6}{2}\\\\x=-3[/tex]
