Answer:
[tex]x+2y-10=0[/tex]
Step-by-step explanation:
Consider an equation: [tex]y=mx+c[/tex]
Here, m is the slope of the line and c is the y-intercept.
Given equation is [tex]y=2x+3.14[/tex]
Here, slope is [tex]m=2[/tex]
As product of slopes of two perpendicular lines is equal to [tex]-1[/tex], slope of the required line is [tex]m_1=\frac{-1}{m}=\frac{-1}{2}[/tex].
Let [tex](x_1,y_1)=(2,4)[/tex]
Equation of the required line is [tex]y-y_1=m_1(x-x_1)[/tex]
[tex]y-4=\frac{-1}{2}(x-2)\\2(y-4)=-1(x-2)\\2y-8=-x+2\\x+2y-8-2=0\\x+2y-10=0[/tex]
