Answer:
A. 109
Step-by-step explanation:
We know that since AB = CB, then ΔABC is isosceles.
Since AC, one of the sides of ΔABC, is on the diameter of circle D, by definition, we know that ΔABC is also a right triangle. Thus, if ΔABC is an isosceles right triangle, then ∠BAC = ∠BCA = 45°.
Draw a line connecting D to B so that we now have isosceles triangle BDC. Since arc BC is 52°, by definition of central angles, ∠BDC is also equal to 52°. Then, ∠DBC = ∠DCB = (180 - 52)/2 = 64°.
∠BCE = ∠DCB + ∠BCA
∠BCE = 64 + 45 = 109°
The answer is thus A.
~ an aesthetics lover
