1. Find an expression for a side length of the square. For this case, the first thing to do is to know that the area of a square is: A = L ^ 2 Where L: side of the square. We then have to factorize the given polynomial: z ^ 2 + 12z + 36 (z + 6) * (z + 6) Rewriting: z ^ 2 + 12z + 36 = (z + 6) ^ 2 Answer: The side of the square is: L = (z + 6) 2. Find the perimeter when z = 12. The perimeter of a square by definition is: P = 4L Where L: side of the square. Substituting we have: P = 4 (z + 6) For z = 12 we have: P = 4 (12 + 6) P = 72
