if exy=3, then dy/dx will be found as follows: differentiating our expression implicitly we get: (x(dy/dx)+y)e^(xy)=0 N/B when differentiating e^(xy) we apply chain rule. When differentiating xy, we use product rule. next, we substitute (1, ln(3)) and solve for dy/dx (1(dy/dx)+ln(3))^(1ln(3))=0 ((dy/dx)+ln(3))e^(ln(3))=0 but e^(ln3)=3, this is because e and ln are inverse of each other.
3((dy/dx)+ln(3))=0 dy/dx+ln (3)=0 dy/dx=-ln(3) The answer is : dy/dx=-ln(3)
