Respuesta :

Exvited
[tex] \frac{2}{5} (z+1)= y \\ \\ \frac{2(z+1)}{5} = y \\ \\ 2(z + 1) = y \times 5 \\ \\ 2(z + 1) = 5y \\ \\ z + 1 = \frac{5y}{2} \\ \\ z = \frac{5y}{2} -1 \\ \\ Answer: \fbox {z = 5y/2 - 1} [/tex]
Billymkhoi
2/5(z+1)=y
⇒ z+1= y/(2/5)
⇒ z+1= y*(5/2)
⇒ z+1= 5y/2
⇒ z= 5y/2 -1

Final answer: z= 5y/2 -1~