The ten's digit of a two digit number is 1 more than 4 times the units' digit. if 63 is subtracted from the number, the order of the digits is reversed. find the number.
Let x be the digit in the tens place and y be the digit in the ones place. so, the digit is xy The ten's digit of a two digit number is 1 more than 4 times the units' digit. x = 4y + 1
63 is subtracted from the number, the order of the digits is reversed 10x + y - 63 = 10y + x 9x - 9y = 63