Answer:
[tex]n\geq-[/tex] the quantity [tex]2[/tex] times c minus [tex]2[/tex] all over p
Step-by-step explanation:
we have
[tex]-np-4\leq 2(c-3)[/tex]
Adds [tex]4[/tex] both sides
[tex]-np-4+4\leq 2(c-3)+4[/tex]
[tex]-np\leq 2c-6+4[/tex]
[tex]-np\leq 2c-2[/tex]
Divide by [tex]p[/tex] both sides
[tex]-np/p\leq (2c-2)/p[/tex]
[tex]-n\leq (2c-2)/p[/tex] -------> Multiply by [tex]-1[/tex]
[tex]n\geq -\frac{(2c-2)}{p}[/tex]
