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You drop a rock off a bridge. The rock’s height, h (in feet above the water), after t seconds is modeled by h = -16t2 + 541. What is the height of the rock after 2 seconds? Question 10 options: 605 feet 477 feet 509 feet –64 feet

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pmayl
Let's plug in 2 for t and solve and h:
h(t) = -16t^2 + 541
h(2) = -16(2^2) + 541
h(2) = -16*4 + 541
h(2) = -64 + 541
h(2) = 477 feet
Answer is b) 477 feet

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