The functions are:
i) [tex]f(t)=0.3t+12[/tex]
ii) [tex]g(t)=0.1t^2-1.7t+15[/tex], where f and g is the number (approximate) of goats in fence area 1, and fence area 2.
After t months, the total number of goats is:
[tex]f(t)+g(t)=0.3t+12+0.1t^2-1.7t+15[/tex], which adding the like terms simplifies to
[tex]f(t)+g(t)=0.1t^2-1.4t+27[/tex].
Thus, our function is [tex]h(t)=(t)+g(t)=0.1t^2-1.4t+27[/tex].
Answer: [tex]h(t)=0.1t^2-1.4t+27[/tex].
