given the points M (-3,-4) and T (5,0), find the coordinates of the point Q on direct line segment MT that partitions MT in the ratio 2:3. Write the coordinates of the point Q in decimal form.

Respuesta :

vector MT, or the change from x1 to x2 and y1 to y2 is expressed as
[tex](5 - ( - 3))i + (0 - ( - 4))j \\ = 8i + 4j[/tex]
no worries if you are unfamiliar with vector notation which is the the I and j there. it just shows that from point m to point t, x increases by 8 and y increases by 4. now find
[tex] \frac{2}{3} 8 \: \: \: \: and \: \: \: \: \frac{2}{3} 4[/tex]
that is
[tex] \frac{16}{3} and \frac{8}{3} [/tex]
add the 16/3 to the original value of x and 8/3 to the original value of y. the original value is point m.

now your point q should equal
[tex]( \frac{16}{3} + ( - 3))x \: \: and \: \: ( \frac{8}{3} + ( - 4))y[/tex]

Answer:

The coordinates of the point Q = (x,y) =(0.2,-2.4)

Step-by-step explanation:

The section formula, (x,y) is the coordinate on line joining two points [tex] (x_1,y_1) , (x_2,y_2)[/tex] in the ratio of m is to n.

[tex]x=\frac{x_1\times n+x_2\times m}{m+n}[/tex]

[tex]y=\frac{y_1\times n+y_2\times m}{m+n}[/tex]

Given the points M (-3,-4) and T (5,0) , on this line joining these point there was another point Q which divides into ratio of 2:3.

[tex] (x_1,y_1) , (x_2,y_2)=(-3,-4) , (5,0)[/tex]

The coordinates of the point Q = (x,y)

m = 2 , n = 3

[tex]x=\frac{-3\times 3+5\times 2}{2+3}[/tex]

[tex]x=\frac{1}{5}=0.2[/tex]

[tex]y=\frac{-4\times 3+0\times 2}{2+3}[/tex]

[tex]y=\frac{-12}{5}=-2.4[/tex]

The coordinates of the point Q = (x,y) = [tex](\frac{1}{5},\frac{-12}{5})=(0.2,-2.4)[/tex]