name the theorem or postulate that lets you conclude triangle ABD is congruent to triangle CBD with only one additional step

Answer:
The answer is the first one ⇒ AAS
Step-by-step explanation:
∵ DB ⊥ AC
∴ m∠DBA = m∠DBC = 90° ⇒ (1)
∵ m∠A = m∠C ⇒ (2) given (from figure)
∵ DB is a common side in the two Δ ⇒ (3)
From (1) , (2) and (3)
∴ Δ ABD is congruent to Δ CBD ⇒ AAS
Answer:
AAS
Step-by-step explanation:
***AAS
SAS
ASA
none of the above