(3,0)(0,4) slope = (4 - 0) / (0 - 3) = -4/3 A perpendicular line will have a negative reciprocal slope. So our perpendicular line has a slope of 3/4
y = mx + b slope(m) = 3/4 (-6,-5)....x = -6 and y = -5 now sub into the formula and find b, the y int -5 = 3/4(-6) + b -5 = -18/4 + b -5 + 18/4 = b -20/4 + 18/4 = b -2/4 = b so ur perpendicular line is : y = 3/4x - 2/4....or 3x - 4y = 2
and ur point (6,4) lies on the perpendicular line <===