Audrey has a bag of similar-sized red and green grapes. There are 12 red grapes and 13 green grapes in the bag. If the first 7 grapes she ate were green what is the probability that the 8th grape she eats is green and the 9th grape she eats is red?

Question

13-12-2017
Mathematics

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Audrey has a bag of similar-sized red and green grapes. There are 12 red grapes and 13 green grapes in the bag. If the first 7 grapes she ate were green what is the probability that the 8th grape she eats is green and the 9th grape she eats is red?

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angelenebear angelenebear · Answer 1 · 2017-12-13T23:33:45+01:00

angelenebear angelenebear

13-12-2017

well, sense she's eaten 7 green grapes there's only 6 of them left. therefore

red grapes = [tex] \frac{12}{25} [/tex]
and green grapes =[tex] \frac{6}{25} [/tex]

probably not very helpful but i tried ^^

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binabahtisrealp0wrkv binabahtisrealp0wrkv · Answer 2 · 2017-12-13T23:35:16+01:00

binabahtisrealp0wrkv binabahtisrealp0wrkv

13-12-2017

50/50 for green and for red that could be 25/50.

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