Respuesta :
in case of earth,
s = v0t + 0.5gt^2
=0+0.5*9.8*(4.1)^2
=82.369 m
in case of planet X, falling from the same distance
82.369 = 0 + 0.5*(9.8/5)*t^2
or,t^2 = 82.369/0.98
or, t = 9.168 s (approx.)
So, it will take around 9.168 s
s = v0t + 0.5gt^2
=0+0.5*9.8*(4.1)^2
=82.369 m
in case of planet X, falling from the same distance
82.369 = 0 + 0.5*(9.8/5)*t^2
or,t^2 = 82.369/0.98
or, t = 9.168 s (approx.)
So, it will take around 9.168 s
The kinematic we find the time it takes for the body to fall on the planet X is 9.17 s
Given parameters
- Acceleration on planet x a = 1/5 g
- The time of fall on the Earth t = 4.1 s
To find
- The fall time on planet X
Kinematics studies the movement of the carpus, establishing relationships between their position, speed and acceleration.
For this exercise we must solve it in parts:
1st part. We look for the distance that the body on the ground in the Earth
y = v₀ t - ½ g t²
Where y and, y₀ are the final and initial height, respectively, g the ground clearance and t the time
where as the body is released its initial velocity is zero
y- y₀ = - ½ g t²
Δy = - ½ 9.8 4.1²
Δy = - 82.4 m
2nd part. This same distance is the one that travels on planet X, we look for time
y - y₀ = - ½ a t²
indicates that the acceleration on planet X is
a = 1/5 g
we substitute
Δy = - ½ (1/5 g) t²
t = [tex]\sqrt{\frac{10 \ \Delta y}{g} }[/tex]
t = [tex]\sqrt{\frac{10 \ 82.4 }{9.8} }[/tex]Ra 10 82.4 / 9.8
t = 9.17 s
In conclusion using kinematics we find the time it takes for the body to fall on planet x is 9.17 s
learn more about kinematics here:
https://brainly.com/question/11910853
