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Notice that "po4" appears in two different places in this chemical equation. po 3−4 is a polyatomic ion called phosphate . what number should be placed in front of na3po4 to give the same total number of phosphate ions on each side of the equation? ?na3po4+mgcl2→mg3(po4)2+nacl

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Yna9141
It can be observed from the given that at the left hand side of the chemical reaction above, there is only only phosphate ion. This can be obtain by the dissociation of Na3PO4. However, there are two phosphate ions on the right hand side of the equation by the dissociation of the Mg3(PO4)2. To equate the number of phosphate ions, we multiply Na3PO4 by 2. 

ANSWER: 2

Answer: "2" should be placed infront of [tex]Na_3PO_4[/tex] to have the same number of phosphate ions on each side.

Explanation: For a given reaction in the question,

The phosphate ions on product side are 2, so there should be 2 phosphate atoms on the reactant side as well.

And the number of Magnesium atoms on product side is 3, there should be 3 magnesium atoms on the reactant side as well.

To balance out Phosphate and magnesium atoms, 6 sodium and chlorine atoms each are formed on reactant side, so to balance these atoms, 6 atoms of each should be present on product side.

Now, the balanced Chemical equation becomes:

[tex]2Na_3PO_4+3MgCl_2\rightarrow Mg_3(PO_4)_2+6NaCl[/tex]

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