With your hand parallel to the floor and your palm upright, you raise a 3-kg book upward with an acceleration of 2 m/s2. what is the magnitude of force that your hand exerts on the book while it is accelerating?

Now to get the correct mass we need to divide its weight by the gravitational field strength(in our case it is just gravity) but first we want our weight of 3kg to be in Newtons.

1 kg = 9.81 N

w = (3)(9.81) = 29.4N

Now that our weight is 29.4N we need to divide that by gravity.

m = [tex]\frac{29.4}{9.8}[/tex]

Now that we have mass we can plug in our numbers

[tex](\frac{29.4}{9.8}*2)+29.4 = 35.4N[/tex]

Plugging that into our calculator gives us the answer 35.4 or 35 N

(feel free to correct me if my reasonings for any of this stuff is incorrect)

onyebuchinnaji onyebuchinnaji · Answer 2 · 2021-10-21T11:25:50+02:00

The magnitude of force that your hand exerted on the book while it accelerates is 35.4 N.

The given parameters;

mass of the book, m = 3 kg
acceleration of the book, a = 2 m/s²

The magnitude of force that your hand exerted on the book while it accelerates is the tension on your hand.

The tension on your hand while the book accelerates is calculated using Newton's second law of motion;

F = ma

T = ma + w

T = ma + mg

T = m(a + g)

T = 3(2 + 9.8)

T = 35.4 N

Thus, the magnitude of force that your hand exerted on the book while it accelerates is 35.4 N.

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