The surface area of the cylinder that forms the "sides" of the microvillus rod is given by the area of the curved surface of a cylinder with diameter (d) = 0.1 μm and height (h) = 1.0 μm.
The curved surface area of a cylinder is given by 2πrh, where r = d / 2 = 0.1 / 2 = 0.05 μm.
Thus, the curved surface area is given by
[tex]2(3.14)(0.05)(1.0) = 3.14 \times 10^{-11}\mu m^2[/tex]
Therefore, the surface area of the cylinder that forms the "sides" of the microvillus rod is [tex]3.14 \times 10^{-11}\mu m^2[/tex]
