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For the function f(x) = (x − 2)2 + 4, identify the vertex, domain, and range. a. The vertex is (–2, 4), the domain is all real numbers, and the range is y ≥ 4. b. The vertex is (–2, 4), the domain is all real numbers, and the range is y ≤ 4. c. The vertex is (2, 4), the domain is all real numbers, and the range is y ≤ 4. d.The vertex is (2, 4), the domain is all real numbers, and the range is y ≥ 4.

Respuesta :

konrad509
[tex]f(x)=a(x-h)^2+k \Rightarrow \text{vertex}=(h,k)\\\\ f(x)=(x-2)^2+4 \Rightarrow \text{vertex}=(2,4)[/tex]

The range of [tex]f(x)=a(x-h)^2+k[/tex] is
[tex]y\leq k[/tex] for [tex]a<0[/tex]
[tex]y\geq k[/tex] for [tex]a>0[/tex]

The domain of any quadratic function is all real numbers.

In [tex] f(x)=(x-2)^2+4[/tex], [tex]a=1\ \textgreater \ 0[/tex], so the range is [tex]y\geq4[/tex]

So it's D.

Answer:

The answer is D. The vertex is (2,4), the domain is all real numbers, and the range is y is greater than or equal to 4

Step-by-step explanation:

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