Letters a, b, c, and d are angles measures.



Which equation is enough information to prove that lines m and n are parallel lines cut by transversal p? Check all that apply.

a = c
a = d
c = d
b + c = 180°
b + d = 180°

Letters a b c and d are angles measures Which equation is enough information to prove that lines m and n are parallel lines cut by transversal p Check all that class=

Respuesta :

When a line intersects two parallel lines, then corresponding angles are formed which means the same corners are congruent, So one of the options is c = d.

And because of vertical angles, a = d is also an answer. Lastly b+d=180, because b+c=180 an c=d therefore b+d=180. Thus the answer is B,C,E. which is a=d, c=d, and b+d=180. Hope this helps, and have a good day!


Hence,  lines [tex]m[/tex] and [tex]n[/tex] are parallel lines cut by transversal [tex]p[/tex].

Step-by-step explanation:

Given: Letters [tex]a,b,c,\;\rm{and} \;d[/tex] are angles measures.

To prove: lines [tex]m[/tex] and [tex]n[/tex] are parallel lines cut by transversal [tex]p[/tex].

From the figure:

[tex]\angle a=\angle c[/tex]                         (Vertically opposite angles)    

[tex]\angle a=\angle d[/tex]                         (Exterior opposite angles)    

[tex]\angle c=\angle d[/tex]                         (Corresponding angles)

[tex]\angle b+\angle c=180^\circ[/tex]              (Linear Pair angle property)

[tex]\angle b+\angle d=180^\circ[/tex]              (Co-exterior angles )

Here, Corresponding angles are formed where a line known as an intersecting transversal, crosses through a pair of parallel lines.

[tex]\angle c\; \& \; \angle d[/tex] are pair of corresponding angles then we can conclude that lines [tex]m[/tex] and [tex]n[/tex] are parallel lines cut by transversal [tex]p[/tex].

Hence Proved.

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