Hence, lines [tex]m[/tex] and [tex]n[/tex] are parallel lines cut by transversal [tex]p[/tex].
Step-by-step explanation:
Given: Letters [tex]a,b,c,\;\rm{and} \;d[/tex] are angles measures.
To prove: lines [tex]m[/tex] and [tex]n[/tex] are parallel lines cut by transversal [tex]p[/tex].
From the figure:
[tex]\angle a=\angle c[/tex] (Vertically opposite angles)
[tex]\angle a=\angle d[/tex] (Exterior opposite angles)
[tex]\angle c=\angle d[/tex] (Corresponding angles)
[tex]\angle b+\angle c=180^\circ[/tex] (Linear Pair angle property)
[tex]\angle b+\angle d=180^\circ[/tex] (Co-exterior angles )
Here, Corresponding angles are formed where a line known as an intersecting transversal, crosses through a pair of parallel lines.
[tex]\angle c\; \& \; \angle d[/tex] are pair of corresponding angles then we can conclude that lines [tex]m[/tex] and [tex]n[/tex] are parallel lines cut by transversal [tex]p[/tex].
Hence Proved.
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