hello : let the slope : a and ; b the slope of the line : 6x - 3y = 2 the line that is perpendicular to 6x-3y=2 so : a×b = - 1 but : 6x - 3y = 2... y = 2x-2/3 when : b = 2 in point - form form of the equation of the line that is perpendicular to 6x-3y=2 is : y = (-1/2)x +c contains (5,1) : 1 = (-1/2)(5) +c c = 7/2 an equation is : y= (-1/2)x +7/2