width= x
length=4x-9
perimeter of a rectangle is the sum of all sides:
Perimeter=2(width)+2 length
In this case:
Perimeter = 382 yd;
then:
2(x)+2(4x-9)=382
2x+8x-18=382
10x=382+18
10x=400
x=400/10=40 (with=40 yd)
(4x-9)=4(40)-9=160-9=151 (length=151 yd)
Answer: the dimensions of the playing field are width=40 yd and length=151 yd.