Answer: The acceleration of the train will be [tex]-0.0625m/s^2[/tex]
Explanation:
Acceleration is defined as the rate of change of velocity of an object.
Mathematically,
[tex]a=\frac{\Delta v}{t}[/tex]
where,
a = acceleration
[tex]\Delta v=v_2-v_1[/tex] = Change in velocity
t = Time
We are Given:
[tex]a=?m/s^2\\v_1=25m/s\\v_2=10m/s\\t=240s[/tex]
Putting values in above equation, we get:
[tex]a=\frac{(10-25)m/s}{240s}=-0.0625m/s^2[/tex]
Negative sign implies this is the negative acceleration.
Hence, the acceleration of the train is [tex]-0.0625m/s^2[/tex]
