Answer: The concentration of the stock solution will be 6.00 M.
Explanation: To calculate the molarity of the stock solution we use the formula:
[tex]M_1V_1=M_2V_2[/tex]
where,
[tex]M_1\text{ and }V_1[/tex] are the molarity and volume of the stock solution.
[tex]M_2\text{ and }V_2[/tex] are the molarity and volume of the HCl solution.
Given:
[tex]M_1=?M\\V_1=35mL\\M_2=1.40M\\V_2=150mL[/tex]
Putting values in above equation, we get:
[tex]M_1\times 35=1.40\times 150[/tex]
[tex]M_1=6M[/tex]
So, the concentration of the stock solution is 6M.
