A student bikes to school by traveling first dN = 1.00 miles north, then dW = 0.600 miles west, and finally dS = 0.200 miles south. Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d⃗ N be the displacement vector corresponding to the first leg of the student's trip. Express d⃗ N in component form

Respuesta :

Refer to the diagram shown below.

Define unit vectors along the x and y axes as respectively [tex]\hat{i} \, and \, \hat{j}.[/tex]

Then the three successive displacements, written in component form, are respectively
[tex]\vec{dN} = 1.0 \, \hat{j} \\ \vec{dW} = -0.6 \, \hat{i} \\ \vec{dS} = -0.2 \, \hat{j}[/tex]

The total displacement for the first leg of the trip is
[tex]\vec{d} = \vec{dN} + \vec{dW} + \vec{dS} \\ \vec{d}= 1.0\hat{j}-0.6\hat{i}-0.2\hat{j} \\ \vec{d}=-0.6\hat{i}+0.8\hat{j}[/tex]

Answer:
[tex]\vec{d} = -0.6\hat{i}+0.8\hat{j}[/tex]   or  (-0.6, 0.8)


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