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A gas has an initial volume of 212 cm3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm3 and the temperature of the gas increases to 308 K? 0.86 atm 0.95 atm 1.0 atm 1.1 atm

Respuesta :

If the ga has 212 cm3 the. Temperature was at a 2

Answer: 1.1 atm

Explanation:

Using ideal gas equation:

[tex]\frac{P_1V_1}{T_1}={P_2V_2}{T_2}[/tex]

[tex]P_1[/tex] = initial pressure = 0.98 atm

[tex]V_1[/tex] = initial volume = [tex]212cm^3[/tex]

[tex]T_1[/tex] = initial temperature= 293 K

[tex]P_2[/tex] = final pressure = ?

[tex]V_2[/tex] = final volume= [tex]196cm^3[/tex]

[tex]T_2[/tex] = final temperature=308 K

[tex]\frac{0.98\times 212}{293}={P_2\times 196}{308}[/tex]

[tex]P_2= 1.1atm[/tex]

Thus final pressure of the gas is 1.1 atm.

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