Please Help please !!! two planes leave Atlanta at 3pm est. one flies east and travels at a speed of 75 kilometers per hour slower than the other plane witch is flying west. by 7 pm est , the planes are 5460 kilometers apart. what is the speed of the plane flying east
Answer:645 kilometers per hour Solution. Let v be the speed of the plane flying east! Then, the speed of the plane flying west is v+75. Since the planes are 5460 kilometers apart by 7 pm est, (7-3)*(v+(v+75))=5460 2v+75=1365, 2v=1290, v=645 answer: 645
