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A rectangle's length is 11 inches greater than its width. if the perimeter of the rectangle is 42 inches, find the length. (all answers are given in inches.)

Respuesta :

42/2=21 (is the sum of both lengths)
2x+11=21
2x=10
x=5

length= 16
width=5

The width is 10 inches.

Rectangle

It is a polygon that has four sides and four vertices. and opposite sides are parallel and all the angles are equal.

Given

Length = 11 inches

Perimeter = 42 inches

Perimeter = 2×( length + width )

To find

The width of the rectangle.

How to find the width of the rectangle?

Length = 11 inches

Perimeter = 42 inches

Then

[tex]\begin{aligned} \rm Perimeter &= \rm 2 *( length + width )\\42 &= 2 \rm (11+w)\\21 &= 11 + \rm w\\\rm w &= 10\\\end{aligned}[/tex]

Thus the width is 10 inches.

More about the rectangle link is given below.

https://brainly.com/question/10046743

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