good, the number in front of the x^2 term is 1
we can move to the next step
take 1/2 of the linear coefient and square it
10 is the linear coefient
10/2=5, (5)^2=25
add that to both sides
x²+10x+25=24+25
factor perfect square trionmial
(x+5)²=49
squaer root both sides
remember to take positive and negative roots
x+5=+/-7
minus 7 both sides
x=-5+/-7
x=-5+7 and -5-7
x=2 annd -12
the 2 soltuions are x=-12 and 2
