[tex] \Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}[/tex]
[tex] \Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}[/tex]
[tex] \Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}[/tex]
[tex] \Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}[/tex]
[tex] \Large f(x) = \frac{(x - 1)(x + 2)(x + 4)}{(x + 1)(x - 2)(x - 4)}[/tex]
Bella says that the function is defined at x = –1, x = 2, and x = 4 so Bella is wrong since the result is undefined because we cannot divide by zero Therefore, Edward is correct.