Respuesta :
(x - 3)^2 = 0
(x - 3)(x - 3) = 0
x^2 - 3x - 3x + 9 = 0
x^2 - 6x + 9 = 0 <===
(x - 3)(x - 3) = 0
x^2 - 3x - 3x + 9 = 0
x^2 - 6x + 9 = 0 <===
Answer:
[tex]x^{2} -6x+9[/tex]
Step-by-step explanation:
This binomial can be solved by the perfect square binomial method. Its standard form is:
[tex](a-b)^{2} = a^{2} -2ab+b^{2}[/tex]
In this way, substituting
[tex]a=x; b=3[/tex]
[tex](x-3)^{2} = x^{2} -2(x)(3)+(3)^{2} = x^{2} -6x+9[/tex]