Respuesta :

apologiabiology
remember that i²=-1

the conjugate of a+bi is a-bi

so
3-4i
the conjugate is 3+4i

product
(3-4i)(3+4i)
hey, this looks familiar
remember (a-b)(a+b)=a²-b²
so
(3-4i)(3+4i)=(3)²-(4i)²=9-(16i²)=9-16(-1)=9+16=25

the product is 25
it's conjugate is 3+4i

The product of 3-4i and its conjugate is equals to 25

The conjugate of  3-4i  is  3+4i . Therefore, we are asked to find the product of   3-4i  and  3+4i .

This can be done as follows:

( 3-4i )( 3+4i)

lets open the bracket by multiplying

9 + 12i - 12i - 16i²

9 - 16i²

i² = - 1

Therefore,

9 - 16(-1) = 9 + 16 = 25

The product of 3-4i and its conjugate  = 25

read more: https://brainly.com/question/2687178?referrer=searchResults

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