Respuesta :

ok, so so we gots from x≤-1 and x≥1 for the bounds

hmm, the x≤-1 one

hmm, looks like the y intercept is -1 and the slope is 2/1
y=2x-1
test (-1,-3)
works
test (-2,-5)
works

yep

2x-1 is first blank



the other one

seems to have y intercept at 4 and slope of 1
y=1x+4
y=x+4
this works because I tested it



top left: 2x-1
top right: x≤-1 or x is less than or equal to -1
bottom left: x=4
bottom left: x≥1 or x is greater than or equal to 1

Answer:

The piecewise function is

[tex]f(x)=\begin{cases}2x-1&\text{ if }x\leq-1\\ x+4&\text{ if } x\geq1 \end{cases}[/tex]

Step-by-step explanation:

From the given graph it is noticed that the graph is divides into two pieces.

The first function is defined for all values of x which are less than or equal to -1. The second function is defined for all values of x which are greater than or equal to 1.

The equation of line which passing through two points is

[tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

The first line is passing trough (-1,-3) and (-2,-5).

[tex]y-(-3)=\frac{-5-(-3)}{-2-(-1)}(x-(-1))[/tex]

[tex]y+3=\frac{-2}{-1}(x+1)[/tex]

[tex]y+3=2(x+1)[/tex]

[tex]y=2x+2-3[/tex]

[tex]y=2x-1[/tex]

For [tex]x\leq-1[/tex] the function is defined as,

[tex]f(x)=2x-1[/tex]

Similarly the second line is passing through (1,5) and (2,6).

[tex]y-5=\frac{6-5}{2-1}(x-1)[/tex]

[tex]y-5=1(x-1)[/tex]

[tex]y=x+4[/tex]

For [tex]x\geq-1[/tex] the function is defined as,

[tex]f(x)=x+4[/tex]

Therefore, the piecewise function is,

[tex]f(x)=\begin{cases}2x-1&\text{ if }x\leq-1\\ x+4&\text{ if } x\geq1 \end{cases}[/tex]