Respuesta :
y < (x - 4)(x + 2)
so the critical points are -2 and 4
(-2,-1) will be in the solution
( 0,-2) will not
(4,0) will not.
the answer is ((-2,-1)
so the critical points are -2 and 4
(-2,-1) will be in the solution
( 0,-2) will not
(4,0) will not.
the answer is ((-2,-1)
Answer:
The correct option is 1. The point (-2,-1) is in the solution set of the given inequality.
Step-by-step explanation:
The given inequality is
[tex]y<x^2-2x-8[/tex]
A point (x₁,y₁) is in the solution set of above inequality if the inequality satisfy by the point (x₁,y₁).
Check the inequality by (-2,-1).
Put x=-2 and y=-1 in the given inequality.
[tex]-1<(-2)^2-2(-2)-8[/tex]
[tex]-1<4+4-8[/tex]
[tex]-1<0[/tex]
This statement is true, therefore the point (-2,-1) is in the solution set of the given inequality.
Check the inequality by (0,-2).
Put x=0 and y=-2 in the given inequality.
[tex]-2<(0)^2-2(0)-8[/tex]
[tex]-2<0-8[/tex]
[tex]-2<-8[/tex]
This statement is false, therefore the point (0,-2) is not in the solution set of the given inequality.
Check the inequality by (4,0).
Put x=4 and y=0 in the given inequality.
[tex]0<(4)^2-2(4)-8[/tex]
[tex]0<16-8-8[/tex]
[tex]0<0[/tex]
This statement is false, therefore the point (4,0) is not in the solution set of the given inequality.
