What are the amplitude, period, phase shift, and midline of f(x) = 2 sin(x + π) − 4?

given that f(x)=2sin(x+π), the standard form of sine function is y=A=sin(Bx+C), with:
A=amplitude
2π/B=period
C/B=phase-shift
A=2=amplitude
B=1
period=2π/B=2π/1=2π
C=2π/1=2π

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PiaDeveau PiaDeveau · Answer 2 · 2019-05-07T08:15:03+02:00

Answer:

Amplitude =2 ,

Time period = [tex]\frac{2\pi }{1}[/tex].

Phase shift = π.

Step-by-step explanation:

Given : f(x) = 2 sin(x + π) − 4.

To find : What are the amplitude, period, phase shift, and midline.

Solution : We have given that f(x) = 2 sin(x + π) − 4.

Standard form of sine function : y=Asin(Bx+C) + D.

Where, A = amplitude , Time period = [tex]\frac{2\pi }{B}[/tex], C = phaseshift

Midline , D = vertical shift.

On comparing

amplitude =2 ,

Time period = [tex]\frac{2\pi }{x}[/tex].

Phase shift = π.

Therefore, amplitude =2 ,

Time period = [tex]\frac{2\pi }{1}[/tex].

Phase shift = π.