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A tank contains 120m ^ 3 of air at atmospheric pressure (100 kPa). It is submerged in water to a depth where the pressure is 450 kPa. What will its volume become at this pressure?

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Answer:

  • 26.7 m³

Explanation:

Given that A tank contains 120m³ of air at atmospheric pressure (100 kPa).

  • Volume of tank at Pressure 100 kPa (P₁) = 120 m³ (V₁)

It is submerged in water to a depth where the pressure is 450 kPa.

  • Volume of tank at Pressure 450 kPa (P₂) = ? (V₂)

Here we have to calculate the volume (V₂) of the air in the tank at 450 kPa.

To Calculate the volume of the air in the tank at 450 kPa, we can use Boyle's law which states that "At constant temperature, the pressure of the gas is inversely proportional to the volume".

P₁V₁ = P₂ V₂

Plug in the values,

100 × 120 = 450 × V₂

12000 = 450 × V₂

V₂ = 12000/450

V₂= 26.7 m³

Therefore, The volume of the air in the tank at 450 kPa is 26.7 m³

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