Answer:
0 and [tex]2\frac{1}{2}[/tex]
Step-by-step explanation:
The meaning of this exercise is to evaluate the expression f(x) for some values of x.
f(2) means you exchange the occurence of x in [tex]f(x) = \frac{x-2}{x+1}[/tex] by 2. This would give the quotient [tex]f(2) = \frac{2-2}{2+1} = \frac{0}{3} = 0[/tex] and similarly for f(-3) you get the quotient [tex]f(-3) = \frac{-3-2}{-3+1} = \frac{-5}{-2} = \frac{5}{2} = 2\frac{1}{2}[/tex]
