contestada

Consider the chemical equation.

2NBr3 + 3NaOH --> N2 + 3NaBr + 3HOBr

If there are 40 mol of NBr3 and 48 mol of NaOH, what is the excess reactant?

N2
NBr3
NaOH
HOBr

Respuesta :

NBr₃ : NaOH = 2 : 3
40    :    48    = 2 : 2.4
40    :    48    = 2.5 : 3

NBr₃ is the excess reactant

NBr₃ is the answer young man.