Answer:
B. [tex]50^{\circ}[/tex].
Step-by-step explanation:
Let the sun be x degrees above the horizon.
We have been given that a skyscraper is 396 meters tall. At a certain time of day, it casts a shadow that is 332 meters long.
We can see from our attachment that skyscraper and shadow forms a right triangle with respect to ground.
We know that tangent relates the opposite side of right triangle to its adjacent, so we can set an equation as:
[tex]\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}[/tex]
[tex]\text{tan}(x)=\frac{396}{332}[/tex]
Using arctan we will get:
[tex]x=\text{tan}^{-1}(\frac{396}{332})[/tex]
[tex]x=50.02407525854^{\circ}\approx 50^{\circ}[/tex]
Therefore, the sun is 50 degrees above the horizon at that time.
