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Write an equation in slope-intercept form of the line perpendicular to y = 3x + 4 that passes through the point (3, 4).
a.y = 3x - 5B)y = 3x + 5C)y = 1/3x + 5D)y = -1/3x + 5

Respuesta :

ghanami

Hello:
the equation is : y = ax+b
the slope is a : a×(3) = -1......( perpendicular to a line with a slope of   3)            because :    y=3x+4    ....  3 is the slope    )     


a = -1/3         y=(-1/3)x+b
the line that passes through (3, 4) :4 = (-1/3)(3)+b
b =5
 the equation is :  y  = (-1/3)x+5

berodiac

Answer:

D) y = -1/3x + 5

Step-by-step explanation:

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