Respuesta :
"pH = - log[H3O+]
13 = - log[H3O+]
-13 = log[H3O+]
Log[H3O+] = -13
Log10 [H3O+] = -13
10^-13 = [H3O+]
[H3O+] = ?"
13 = - log[H3O+]
-13 = log[H3O+]
Log[H3O+] = -13
Log10 [H3O+] = -13
10^-13 = [H3O+]
[H3O+] = ?"