The centripetal acceleration of the mass is 10 m/s².
The centripetal acceleration of the mass when it is at the lowest position is calculated as follows;
Tsinθ = ma - mg
where;
when the mass is at the lowest position, θ = 0
The centripetal acceleration of the mass is calculated as follows;
T sin (0) = ma - mg
0 = ma - mg
ma = mg
a = g
Given that g, acceleration due to gravity = 10 m/s²
Hence, a = 10 m/s²
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The complete question is below:
A mass m is suspended by a massless string forming a simple pendulum of length 2.0 m. The string of the pendulum is initially at an angle of 60° with the vertically downward direction when the mass is released from rest. Calculate the centripetal acceleration of the mass when it is at the lowest position ( take g = 10 m/s²).