Step 1. The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light, impacts a substance. The energy of the photon will be sum total of energy needed to remove the electron and kinetic energy of the released electron.
hf = ϕ + k
where, ϕ = work function
k = kinetic energy
hf = incident of energy
f = c / lamda
Step 2.
Given,
ϕ = 2.45ev
lamda = 4.0 * 10-7m
hc/lamda = ϕ + k
k = (hc/lamda) – ϕ
k = (6.62 * 10-34 * 3 *108 / 4.0 * 10-7) – 2.45 * 1.6 * 10-19
k = 1.045 * 10-19 Joules
Now,
½ mv2= k
V = (2k/m)0.5
V = {(2 * 1.045 * 10-19) / 9.1 * 10-31}0.5
V = 479239.32 m/s
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