The distance that the bullet penetrates is 0.03m.
Given data:
The mass of the bullet is
m = 25 g = 0.025 kg
The bullet's initial velocity is
u = 350 m/s
The final velocity of the bullet is
v = 0
The average force opposing the motion is
F = 50000N
From Newton's second law, the acceleration derived as,
F = m. a.
a = F. m..........(1)
Substituting values in equation (1), we get:
a = 50000 N / 0.025 kg = 2×106 m/s 2
The equation of motion is,
v 2=u 2−2 a S
2 a S=u 2−v 2
S = u 2−v 2/2 a.......(2)
Substituting values in equation (2), we get:
S = (350 m/s)2−0/2(2×106 m/s 2)
=12.25×104 m/s 4×106 m/s 2=0.03m
here, the distance that bullet penetrates is 0.03m.
Kinetic energy has the following formula: K.E. = 1/2 m v 2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kg/m per second squared if the mass is measured in kg and the velocity is measured in meters per second.
Radiant, thermal, electrical, and mechanical kinetic energies are the basic categories.
Learn more about kinetic energy here:
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