High cholesterol: A group of eight individuals with high cholesterol levels were given a new drug that was designed to lower cholesterol levels. Cholesterol levels, in milligrams per deciliter, were measured before and after treatment for each individual, with the following results: Individual Before After 244 207 288 216 274 188 278 200 233 173 271 224 295 171 275 187 4 Download data Part 1 out of 2 Construct a 95% confidence interval for the mean reduction in cholesterol level. Let d represent the cholesterol level before treatment minus the cholesterol level after. Use the TI-84 calculator and round the answers to one decimal place. A 95% confidence interval for the mean reduction in cholesterol level is Hd

The t-distribution is used when the standard deviation for the population is not known, and the bounds of the confidence interval are given according to the following rule:

[tex]\overline{x} \pm t\frac{s}{\sqrt{n}}[/tex]

In which the variables of the equation are presented as follows:

[tex]\overline{x}[/tex] is the sample mean.

t is the critical value.

n is the sample size.

s is the standard deviation for the sample.

The critical value, using a t-distribution calculator, for a two-tailed 95% confidence interval, with 8 - 1 = 7 df, is t = 2.3646.

From the image given at the end of the answer, the sample of the differences is given as follows:

37, 72, 86, 78, 60, 47, 124, 88.

Hence the parameters are given as follows:

[tex]\overline{x} = 74, s = 27.1, n = 8[/tex]

Then the lower bound of the interval is of:

74 - 2.3646 x 27.1/square root of 8 = 51.3.

The upper bound of the interval is of:

74 + 2.3646 x 27.1/square root of 8 = 96.7.

Missing Information

The table is given by the image shown at the end of the answer.

More can be learned about the t-distribution at https://brainly.com/question/17073112

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