Five moles of a monatomic ideal gas expand adiabatically, and its temperature decreases from 370 to 290 K. Determine (a) the work done (including the algebraic sign) by the gas, and (b) the change in its internal energy.

Respuesta :

The total of heat transmitted and work performed represents the change in internal energy of a system. Change in internal energy, U is -12166.20876 J .

Find the solution ?

No. of moles, n = 8.41

Change of temperature, ΔT = T1 - T2

= 395 - 279

= 116 K

For monatomic gas, γ = 5/3

γ -1 = 2 /3

Work done,

plugging values we get

12166.20876 J

Work done, W = + 12166.20876 J

From first law of thermodynamics, dQ = U + W

but, dQ = 0 ( adiabatic process)

Hence, U = - W

= - 12166.20876

Change in internal energy, U = - 12166.20876 J

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